Chapter 2: Describing Movement in One Dimension, 1-D Linear Kinematics

2.3 Time, Velocity, and Speed

Authors: Paul Peter Urone, Roger Hinrichs
Adapted by: Rob Pryce, Alix Blacklin

 

Learning Objectives

By the end of this section, you will be able to:

  • Explain the relationships between instantaneous velocity, average velocity, instantaneous speed, average speed, displacement, and time.
  • Calculate velocity and speed given initial position, initial time, final position, and final time.
  • Derive a graph of velocity vs. time given a graph of position vs. time.
  • Interpret a graph of velocity vs. time.
A group of swimmers in a triathlon swim through a lake
Figure 2.8 The motion of these triathletes during the swim can be described by their speeds and their velocities. (credit: Jon Del Rivero, Unsplash)

There is more to motion than distance and displacement. Questions such as, “How long does a triathlon race take?” and “What was the swimmer’s speed?” cannot be answered without an understanding of other concepts. In this section we add definitions of time, velocity, and speed to expand our description of motion.

Time

As discussed in Physical Quantities and Units, the most fundamental physical quantities are defined by how they are measured. This is the case with time. Every measurement of time involves measuring a change in some physical quantity. It may be a number on a digital clock, a heartbeat, or the position of the Sun in the sky. In biomechanics, the definition of time is simple—time is change, or the interval over which change occurs. It is impossible to know that time has passed unless something changes.

The amount of time or change is calibrated by comparison with a standard. The SI unit for time is the second, abbreviated s. We might, for example, observe that a certain pendulum makes one full swing every 0.75 s. We could then use the pendulum to measure time by counting its swings or, of course, by connecting the pendulum to a clock mechanism that registers time on a dial. This allows us to not only measure the amount of time, but also to determine a sequence of events.

How does time relate to motion? We are usually interested in elapsed time for a particular motion, such as how long it takes a triathlete to complete the transition from swimming to cycling (also known as ‘T1’ in triathlon). To find elapsed time, we note the time at the beginning and end of the motion and subtract the two. For example, the triathlete may exit the swim at 11:04 A.M. and begin the bike portion of the race at 11:08 A.M., so that the elapsed time for T1 would be 4 min.

Elapsed time is calculated as:

[latex]\Delta t = t_f - t_i[/latex]

where
[latex]\Delta t[/latex] is the change in time or elapsed time,
[latex]t_f[/latex] is the time at the end of the motion, and
[latex]t_i[/latex] is the time at the beginning of the motion.

(As usual, the delta symbol, [latex]\Delta[/latex], means the change in the quantity that follows it.)

Life is simpler if the beginning time [latex]t_i[/latex] is taken to be zero, as when we use a stopwatch. If we were using a stopwatch, it would simply read zero at the start of the transition (end of swim) and 4 min at the end (start of the bike). If [latex]t_i = 0[/latex], then [latex]\Delta t = t_f[/latex].

In many examples in this text (and in biomechanics), for simplicity’s sake,

  • motion starts at time equal to zero ([latex]t_i = 0[/latex])
  • the symbol [latex]t[/latex] is used for elapsed time unless otherwise specified:
    ([latex]\Delta t = t_f = t[/latex])

Velocity

Your notion of velocity is probably the same as its biomechanical definition. You know that if you have a large displacement in a small amount of time you have a large velocity, and that velocity has units of distance divided by time, such as miles per hour or kilometers per hour. Velocity is defined as the rate of change of position.

Velocity can be calculated as:

[latex]\bar{v} = \frac{\Delta x}{\Delta t} = \frac{x_f - x_i}{t_f-t_i}[/latex]

where [latex]\bar{v}[/latex] is the average velocity,
[latex]\Delta x[/latex] is the change in position (or displacement),
and [latex]x_f[/latex] and [latex]x_i[/latex] are the final and beginning positions at
times [latex]t_f[/latex] and [latex]t_i[/latex], respectively.

If the starting time [latex]t_i[/latex] is taken to be zero, then the velocity is simply:

[latex]\bar{v} = \frac {\Delta x} {t}[/latex]

 

Notice that this definition indicates that velocity is a vector because displacement is a vector. It has both magnitude and direction. The SI unit for velocity is meters per second or m/s, but many other units, such as km/h, mi/h (also written as mph), and cm/s, are in common use. Suppose, for example, an airplane passenger took 5 seconds to move −4 m (the negative sign indicates that displacement is toward the back of the plane). His average velocity would be:
[latex]\bar{v} = \frac {\Delta x} {t} = \frac {-4m}{5s} = -0.8 m/s[/latex]

The minus sign indicates the average velocity is also toward the rear of the plane.

Importantly, the average velocity of an object does not tell us anything about what happens to it between the starting point and ending point, however. For example, we cannot tell from average velocity whether the airplane passenger stops momentarily or backs up before he goes to the back of the plane. To get more details, we must consider smaller segments of the trip over smaller time intervals.

Airplane shown from the outside. Vector arrows show paths of each individual segment of the passenger’s trip to the back of the plane.
Figure 2.9 A more detailed record of an airplane passenger heading toward the back of the plane, showing smaller segments of his trip.

The smaller the time intervals considered in a motion, the more detailed the information. When we carry this process to its logical conclusion, we are left with an infinitesimally small interval. Over such an interval, the average velocity becomes the instantaneous velocity or the velocity at a specific instant. A car’s speedometer, for example, shows the magnitude (but not the direction) of the instantaneous velocity of the car. (Police give tickets based on instantaneous velocity, but when calculating how long it will take to get from one place to another on a road trip, you need to use average velocity.) Instantaneous velocity, [latex]v[/latex], is the average velocity at a specific instant in time (or over an infinitesimally small time interval).

Mathematically, finding instantaneous velocity, [latex]v[/latex], at a precise instant [latex]t[/latex] can involve taking a limit, a calculus operation beyond the scope of this text. However, under many circumstances, we can find precise values for instantaneous velocity without calculus. This is often done in biomechanics practice by measuring position (or displacement) over very small intervals of time, such as many hundreds of times per second. In many cases, average velocity will be lower than instantaneous velocity, for instance if the object is speeding up or slowing down during the measurement interval.

Speed

In everyday language, most people use the terms “speed” and “velocity” interchangeably. In biomechanics, however, they do not have the same meaning and they are distinct concepts. One major difference is that speed has no direction. Thus speed is a scalar. Just as we need to distinguish between instantaneous velocity and average velocity, we also need to distinguish between instantaneous speed and average speed.

Instantaneous speed is the magnitude of instantaneous velocity. For example, suppose the airplane passenger at one instant had an instantaneous velocity of −3.0 m/s (the minus meaning toward the rear of the plane). At that same time his instantaneous speed was 3.0 m/s. Or suppose that at one time during a shopping trip your instantaneous velocity is 40 km/h due north. Your instantaneous speed at that instant would be 40 km/h—the same magnitude but without a direction. Average speed, however, is very different from average velocity. Average speed is the distance traveled divided by elapsed time.

Average speed can be calculated by:

[latex]\bar {s} = \frac {d_{total}} {\Delta t}[/latex]

where
[latex]\bar{s}[/latex] is average speed, and
[latex]d_{total}[/latex] is total distance, and
[latex]\Delta t[/latex] is elapsed time

We have noted that distance traveled can be greater than the magnitude of displacement. So average speed can be greater than average velocity, which is displacement divided by time. For example, if you drive to a store and return home in half an hour, and your car’s odometer shows the total distance traveled was 6 km, then your average speed was 12 km/h. Your average velocity, however, was zero, because your displacement for the round trip is zero. (Displacement is change in position and, thus, is zero for a round trip.) Thus average speed is not simply the magnitude of average velocity.

A house and a store, with a set of arrows in between showing that the distance between them is 3 point 0 kilometers and the total distance traveled, delta x total, equals 0 kilometers.
Figure 2.10 During a 30-minute round trip to the store, the total distance traveled is 6 km. The average speed is 12 km/h. The displacement for the round trip is zero, since there was no net change in position. Thus the average velocity is zero.

Graphing position, velocity and time

Another way of visualizing the motion of an object is to use a graph. A plot of position or of velocity as a function of time can be very useful. For example, for this trip to the store, the position, velocity, and speed-vs.-time graphs are displayed in Figure 2.11. (Note that these graphs depict a very simplified model of the trip. We are assuming that speed is constant during the trip, which is unrealistic given that we’ll probably stop at the store. But for simplicity’s sake, we will model it with no stops or changes in speed. We are also assuming that the route between the store and the house is a perfectly straight line.)

Three line graphs. First line graph is of position in kilometers versus time in hours. The line increases linearly from 0 kilometers to 6 kilometers in the first 0 point 25 hours. It then decreases linearly from 6 kilometers to 0 kilometers between 0 point 25 and 0 point 5 hours. Second line graph shows velocity in kilometers per hour versus time in hours. The line is flat at 12 kilometers per hour from time 0 to time 0 point 25. It is vertical at time 0 point 25, dropping from 12 kilometers per hour to negative 12 kilometers per hour. It is flat again at negative 12 kilometers per hour from 0 point 25 hours to 0 point 5 hours. Third line graph shows speed in kilometers per hour versus time in hours. The line is flat at 12 kilometers per hour from time equals 0 to time equals 0 point 5 hours.
Figure 2.11 Position vs. time, velocity vs. time, and speed vs. time on a trip. Note that the velocity for the return trip is negative.

Making Connections: Take-Home Investigation—Getting a Sense of Speed

If you have spent much time driving, you probably have a good sense of speeds between about 10 and 70 miles per hour. But what are these in meters per second? What do we mean when we say that something is moving at 10 m/s? To get a better sense of what these values really mean, do some observations and calculations on your own:

  • calculate typical car speeds in meters per second
  • estimate jogging and walking speed by timing yourself; convert the measurements into both m/s and mi/h
  • determine the speed of a sprinter, cyclist, and baseball (use estimates of distance and time)

Check your Understanding

A commuting cyclist travels from home to work, and back in 1 hour and 45 minutes. The distance between the two locations is approximately 13 miles. What is (a) the average velocity of the cyclist, and (b) the average speed of the cyclist in m/s?

(a) The average velocity of the cyclist is zero because [latex]{x}_{f}={x}_{0}[/latex]; the cyclist ends up at the same place they start.

(b) The average speed of the train is calculated below. Note that the cyclist travels 13 miles one way and 13 miles back, for a total distance of 26 miles.

[latex]\frac{\text{distance}}{\text{time}}=\frac{\text{26 miles}}{\text{105 minutes}}[/latex]

 

[latex]\frac{\text{26 miles}}{\text{105 minutes}}×\frac{\text{5280 feet}}{\text{1 mile}}×\frac{\text{1 meter}}{3\text{.}\text{28 feet}}×\frac{\text{1 minute}}{\text{60 seconds}}=\text{6.6 m/s}[/latex]

License

Icon for the Creative Commons Attribution 4.0 International License

Introduction to Biomechanics Copyright © 2022 by Rob Pryce is licensed under a Creative Commons Attribution 4.0 International License, except where otherwise noted.

Share This Book